If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X^2-X-30=
We move all terms to the left:
X^2-X-30-()=0
We add all the numbers together, and all the variables
X^2-1X=0
a = 1; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·1·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*1}=\frac{0}{2} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*1}=\frac{2}{2} =1 $
| -24I-a=-15 | | 26=15w+11 | | 3x-x+5=2x+12 | | 22(g-1=2g+8 | | 15t+10=17t | | c/3+17=25 | | 4x+2+2x-14=180 | | 3/4(x-16)=-2x(x-3)+4 | | 6t-34=-10 | | 8x+14+2x+26=180 | | 12c-10c=14 | | 5t-18=5t-18 | | 5t–18=5t-18 | | 3z-38=z+36 | | x+80-180=x | | x+30+x-30+50+70=360 | | 7d-2d=10 | | x+12=-3x+32 | | (n/5)-4=11 | | x+5+2x-5=53 | | (y+26)+(6y+40)=360 | | x2=-62 | | 12(t+4)=120 | | 16=5e−4 | | 4y+8=5y-12 | | |4x+3|=|2x-5| | | 2x+4=3x-5=2x+2 | | 1203=3j+3 | | 5c+9=13c+1 | | 10t-9=7t+18 | | 5x×15=8x | | 11+d/6=22 |